On Wed, 7 Jan 2009, Dhiren wrote:

This topic is libcurl related so the curl-library is clearly a more suitable
mailing list!

> 1. i had used diffrent formate to send data .
> //char *request = "GET https://202.189.252.134:80 HTTP/1.1\r\n";
> char *request = "GET / HTTP/1.1\r\nHost: 202.189.252.134\r\nConnection:
> Close\r\n\r\n";
> // char *request = "connect to server.";
>
> for curl_easy_send. and it's return CURLE_OK. but getting problem in
> curl_easy_recv
> it's return proxy error :
> HTTP/1.1 502 Proxy Error ( The Uniform Resource Locator (URL) does not use a
> recognized protocol. Either the protocol is not supported or the request was
> not typed correctly. Confirm that a valid protocol is in use (for example,
> HTTP for aWeb request). )

Why are you doing this complicated anyway? Why can't you just send the stuff
using the "normal" way?

"GET /" is not a legal request to a proxy so of course it'll return an error
back. See RFC2616 for details.

> 2. when using
> char *request = "connect to server."; // for send buffer
> and at server a application listning the port 443 and when get connect send
> a response on same socket.
> then getting response null curl_easy_recv. and CURLcode = CURLE_AGAIN
>
> so please give me the solution where i am going wrong.

CURLE_AGAIN is quite a normal situation. What's the problem with that?

> please help me it's very urgent .

Isn't it always? If you really want a fast solution my advice is: use a
traditional libcurl approach and consider hiring a professional to do it for
you.

-- 
  / daniel.haxx.se
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