curl-and-python

Re: Curl.perform() never returns

From: Oleg Pudeyev <oleg+pycurl_at_bsdpower.com>
Date: Fri, 10 Oct 2014 16:04:03 -0400

Have you set pycurl.VERBOSE flag? This should provide some diagnostics.

Oleg

On Wed, 8 Oct 2014 22:09:57 +0000
"Mills, Craig" <cmills_at_Airbiquity.com> wrote:

> I am working with PycURL and libcURL in an embedded environment. We
> are using PycURL v.7.19.0, and libcURL v.7.31.0. We are running
> Python 2.7 on the Windows Compact Embedded 7 hardware.
>
> We are seeing a spurious bug which is very hard to reproduce. We
> have added logging statements, and what we have found is that
> sometimes, for some reason, when we make the PycURL call into the
> perform() method, it just never seems to return from there.
>
>
> I found a timeout bug (fixed in 7.34.0) at:
>
> http://sourceforge.net/p/curl/bugs/1298/?page=0
>
> ...but that seems to be specific to using CurlMulti, and our code is
> simply using what I understand to be the curl_easy wrapper. We just
> use pycurl with the call:
>
> c = pycurl.Curl()
> ...
> c.perform()
>
>
> We are setting a timeout of 65, but from our debug logs it simply
> never returns from the c.perform() call.
>
>
> I am researching how to build our libcurl implementation with debug
> enabled... so any tips there would be appreciated.
>
> Questions:
>
> 1) Are there other timeout bugs I may have overlooked, which may
> have been fixed between 7.31 and newest libcURL?
>
> 2) Does anyone have suggestions for other things to try?
>
>
>
> Thank you so much!
>
>
>
>

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Received on 2014-10-10