Hi,

I have compiled libcurl (version 7.10.8) as a static library under Linux (RHEL2.1).For some reason when i use the static

library and call curl_easy_getinfo for curlinfo_content_type(to get the content type) i get a 43 error code. I use the function exactly the same as in the
examples. Is there a certain way to compile the static library that I'm not aware of?

thank you.

 ______________________________
Yehuda Callen
NDS Technologies Israel Ltd.
E-Mail: ycallen_at_ndsisrael.com
Mobile: 972-67-718-228
Phone: 972-2-589-4613
Fax : 972-2-589-4900
 

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Received on 2004-01-28