Re: Problem with curl_easy_getinfo
Date: Fri, 25 Jun 2004 20:59:22 +0200
I have got one more question.
Cause I am really beginner, could you tell me how to write simple program
which will store a content of webpage into char variable.
thanks a lot
----- Original Message -----
From: "codemastr" <codemstr_at_ptd.net>
To: "libcurl development" <curl-library_at_cool.haxx.se>
Sent: Friday, June 25, 2004 7:15 PM
Subject: Re: Problem with curl_easy_getinfo
> The response code is the HTTP response code. For example, 404 when a page
> not found, 500 when the server has an error, 401 when authentication
> etc. It is not the contents of the page. If you want to retrieve the
> contents of the page, then you need to look at the CURLOPT_WRITEFUNCTION
> -- codemastr
> ----- Original Message -----
> From: "Marek Elsner" <marek_at_icom.pl>
> To: <curl-library_at_cool.haxx.se>
> Sent: Friday, June 25, 2004 1:05 PM
> Subject: Problem with curl_easy_getinfo
> I am newbie, so probably my problem will sound funny.
> If I want to write last URL into variable "m" I am using
> curl_easy_getinfo(curl,CURLINFO_EFFECTIVE_URL,&m); and everything is ok.
> Now I would like to write whole content of the webpage into "m" variable.
> So I think I should use CURLINFO_RESPONSE_CODE, but when I am trying to
> (curl,CURLINFO_RESPONSE_CODE,&m); it does not work.
> On http://curl.haxx.se/libcurl/c/curl_easy_getinfo.html I read that
> CURLINFO_RESPONSE_CODE will pass a pointer to a long.
> But content of the page will not be long ( I suppose long means long int).
> Maybe someone will show me where I made it wrong because now I am totally
> Marek Elsner
Received on 2004-06-25