Hi all,

I am programming Visual C with curl library. I try to capture an image from a server to process. If I use:

curl_easy_setopt(curl, CURLOPT_URL, "http://192.168.1.226/jpg/image.jpg | djpeg -bmp -grayscale > image222.bmp"

There's no error. However, I do not find the image222.bmp.

For the curl command line, that's okie.

Please help me. Thank you.
Hien
Received on 2005-03-24