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RE: libcurl and libssh2

From: Xu, Qiang (FXSGSC) <>
Date: Fri, 23 Oct 2009 19:28:41 +0800

> -----Original Message-----
> From:
> [] On Behalf Of Xu,
> Qiang (FXSGSC)
> Sent: Friday, October 23, 2009 5:54 PM
> To: libcurl development
> Subject: RE: libcurl and libssh2
> For file download/upload, it can be achieved by a series of
> curl_easy_setopt() and curl_easy_perform(). If the URL is
> ended with a slash, curl_easy_setopt() and
> curl_easy_perform() can also be used to fulfill the "ls"
> task. But the result of curl_easy_perform() is CURLE_OK or
> not. I can't see any way to retrieve the "ls" result from
> this function.
> Or, to retrieve the "ls" result, is there any other func to use?

After some research, I feel that maybe curl_easy_setopt() and curl_easy_perform() still can be used without the need for any other func:
/* from */

Data pointer to pass to the file write function. If you use the CURLOPT_WRITEFUNCTION option, this is the pointer you'll get as input. If you don't use a callback, you must pass a 'FILE *' as libcurl will pass this to fwrite() when writing data.

The internal CURLOPT_WRITEFUNCTION will write the data to the FILE * given with this option, or to stdout if this option hasn't been set.

If you're using libcurl as a win32 DLL, you MUST use the CURLOPT_WRITEFUNCTION if you set this option or you will experience crashes.

This option is also known with the older name CURLOPT_FILE, the name CURLOPT_WRITEDATA was introduced in 7.9.7.
If this option is set with a valid file pointer, I guess the "ls" result displayed in stdout will be redirected to the file. Next week, I'll try to write a small program to verify it.

Xu Qiang
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Received on 2009-10-23