Re: debug CURLOPT_POSTFIELDS url?

On Thu, 10 Oct 2019, ka sc via curl-library wrote:

> url_flags = "\"[\\\"INSERT INTO foo2 values(1,11)\\\"]\"";
> curl_easy_setopt(curl, CURLOPT_POSTFIELDS, url_flags.c_str());
>
> Is there a way to see the output url so I can try that in commandline?

The data you set with CURLOPT_POSTFIELDS is not part of the URL - it is part
of the request body - so seeing the URL won't help you.

You can see the URL with CURLOPT_VERBOSE set to 1L, but since you probably
rather see the request body so that you get to see what you post you want to
add a CURLOPT_DEBUGFUNCTION callback and show the data that way.

Possibly based on this example code: https://curl.haxx.se/libcurl/c/debug.html

Alternatively, you make a command line version of the request with curl that
works and then you convert that to libcurl code with the "--libcurl code.c"
option.

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