If the code you posted was copied and pasted from the source, you're missing a ");" on the end of this line:

curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1

JFYI

Dan O.

 --- On Thu 03/04, wrote:

Subject: Operation timed out, error #28

Hello,

I've just started using the php curl functions. My
hosting service just installed curl 7.10.4 for me
(they were running 7.9.5), and they are running php
4.3.3 on an apache / linux server.

I've tried several examples that I have found on the
web for testing curl functionality and get a time out
error #28 with all of them. Here's an example of some
test code:

$url = "http://www.zend.com";;
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_FAILONERROR, 1);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_TIMEOUT, 5);
$result = curl_exec($ch);
echo $result;

print_r(curl_getinfo($ch));
echo '<br>errno:'.curl_errno($ch);
echo '<br>error:'.curl_error($ch);
echo '<br>'.$buffer;
echo '<br>ver:'.curl_version ();

curl_close($ch);

Changing the curlopt_timeout parameter to a high
number of seconds still results in a timeout.

Any thoughts? Is this a code problem or possibly a
php/curl environment problem? Should php have been
recompiled after the new version of curl was
installed?

Any suggestions would be greatly appreciated!

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Received on 2004-03-06