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RE: Problem in posting filename=""

From: <>
Date: Fri, 12 Dec 2008 12:18:35 +0530

        Thank's for the promt reply
Actually when I am trying the following curl_formadd,
And then seeing the debug file, the form which is sent by curl
application has nothing like
That means curl has not made any form with null file name like in

Content-Disposition: form-data; name="name:_id11"; filename=""
Content-Type: application/octet-stream

Then, I tried with
               CURLFORM_COPYNAME, "CarFinderForm:_id11",
                   CURLFORM_CONTENTTYPE ,"application/octet-stream",
But it is giving me the error that filename is NULL

Actually the problem is I have to post the form data which has filename
filed as ""
Also, if we see the form with view souce to the actual page
It has name:_id11 as the filed name but no filename field is there in
the actaul page.


-----Original Message-----
[] On Behalf Of Dan Fandrich
Sent: Thursday, December 11, 2008 11:56 PM
Subject: Re: Problem in posting filename=""

On Thu, Dec 11, 2008 at 06:30:12PM +0530,
> My problem is that I have to post the Form-data as exactly same
> as i got from Live HTTP Header output.
> This is Live HTTP header output:
> Content-Disposition: form-data; name="name:_id11"; filename=""
> Content-Type: application/octet-stream
> -----------------------------1496212324596
> Can anyone sugget me how to do this with curl_formadd( )
> I am trying something like :
> curl_formadd(&formpost,&lastptr,
> But not able to form the exact form data.

Well, what does that give you?

I'm able to replicate the output above with the curl command:

curl -F 'name:_idll=@/dev/null;type=application/octet-stream;filename='

You can look at formparse() in src/main.c to see how that builds the

>>> Dan

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Received on 2008-12-12